Problem
Statement:
Write a
program to a make rectangle by taking the length and breadth as inputs (in the
form of rows and columns) and give output in the following manner:
(In simple words, we have printed
stars (*) on the boundary positions of the matrix and on the centre positions
of the matrix we have printed blank space( ) )
THE CODE:
Sample
Outputs:
In the
above program, two int variables r and c to define the
number of rows and columns respectively.
On line 7
and line 9, following two statements are used to accept the input from the
user:
int
r=sc.nextInt();
int
c=sc.nextInt();
For taking
the input Scanner class has been used, more about Scanner class
Algorithm:
Two for loops are defined:
·
First for loop with counter variable i has initial value 1, conditional
statement i less than or equal to r and an updating statement i++.
·
Inside the first loop there is a second for loop, with counter variable j has initial value 1, conditional
statement j less than or equal to c and an updating statement j++.
Inside the body of this for statement there is an if-else
condition, whose basic aim is to print star (*) on the boundary positions and
print a blank space on the non-boundary positions of the matrix.
You can see on the line 15 of the program, the if statement has four conditions (i.e.,
i==1 || j==1 ||
i==r || j==c) with
logical or operators which means only one condition is sufficient to
execute the body of the if
statement. Inside its body there is a star (*) print statement. On careful
observation, one can easily see that the if statement is true only if
the value of i and j points at a boundary position of the matrix.
If none of the four conditions of the if statement is satisfied, then else's body will execute a print statement to print blank space.
·
After the second loop terminates there is a print statement who's only
work is to change the row in the output after the second for loop terminates.
·
Again, the first for loop’s condition is checked and if it is true
then the algorithm continues.
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